Question

The instantaneous value of current i (amps) att seconds in a circuit is given by i = 35 sin(400xt - 2.5 Find the value of a) The amplitude b) The period in ms Round your answer to 2 decimal places. The frequency

can you break down these answers for me please

Answer 1

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460) the given equation is i=35 sin (2007+ - 2.5) - 0 We know that the general form of sinuson equation is y= A sin (B(xt()) + D - Where A is the amplitude (a) Re-writing » as = 35 sin (4602(t-26.)) i=35 sin (400m (t - toot)) Comparing ③ and the amplitude A=35 (b) Period za = - Zoo secs 400 Period = 0.005 see. or period = 0.005 x 1000 ms I Period= 5 ms (e) Frequency = 1 1 1 I = (200 Hz = F | le 200 times per second.. (ca) We know that in y= Asin (Bx +C) Ć denotes the initial phase angle (in radians). so from 0, [c=-2.5 radians 1 and c =-2.5x 180 degree = -143:20 degree Value of i at t= 10.6 . è = 35 sin (Moon (lool) - 2.5) = 35 sin (40404-25) = 35 sin (12689.53) in radian) = 35 sin (727056.76). (in degree) = 35 (-0.5984) - -20.4465 orlí = 20.94657 60

o We know that ê= 35 sin (400 It-2.5) è will be manimum when sin (400 It-25)=1. = sin(4.5024-2-5) = sin(21 41/ą 1m20,62, - - 400 AE- 5 = (2n +1) K . 40o At Rn ta u oa (en Hats t= dood [2012+5] so for the first time imaxe, when uzo le tmax - Strona 12.0++5] - tmar = A + 3 coa adoot took tman = 0.0032 second tmax = 0.0032 x 1000 Itman = 3.23 ms] or