Question

If 1.11x1020 electrons flow through a cross section of a 2.96 mm diameter Gold wire in 5.53 s, then what is the drift speed of the electrons? (The density of conduction electrons in Gold is n = 5.90x1028 1/m3.) 4.94x10-2 mm/s (in mm/s)

Answer 1

the current equation conductor is. lishe audl n-No.ofé per unit volume e-election charge A- Cross sectional Area Od-drift velocity - current is l.lox lop0x1681019 Mumbero e aree i- og - 5.53 = 0.198X10 POXl6y1019 i = 1,98x188x1,6x1079 i = 3:18 Amp i

iz neaud He diameter Va = The A wat met >= dligen 40 e 90 1-62166x58 yiek klos 1. 3.18 xió 9x 5.9 X 10P8 X100 up = 0.0489x163 m/sec j od = 4.9 x162 mm Igec