Question

You work for Whiting-Turner in their transportation division and are given the following rush hour data; the probability of a car being stopped at a particular intersection P(A) is 0.4 and the probability of a car addition, the probability that a car gets stopped at both lights P(An B) is 0.15 Calculate the following: being stopped at the second intersection, P(B) is 0.3. In f. What is the probability that a car will be stopped at least once at these two intersections? g. A camera at the first intersection sees that a car is stopped. What is the probability that the car will be stopped at the second intersection?

Answer 1

Ans:

f)

P(at least once)=P(either at A or B)

=P(A)+P(B)-P(A and B)

=0.4+0.3-0.15

=0.55

g)

P(B/A)=P(A and B)/P(A)=0.15/0.4=0.375