A) How many of the following are found in 1500 g of benzene (C6H6)? kg C6H6...
A) How many of the following are found in 1500 g of benzene (C6H6)?
kg C6H6
mol C6H6
lb-mole C6H6
mole (g-mole) C
mol H
g C
g H
molecules of C6H6
B) A mixture of methanol and methyl acetate contains 45.0 wt% methanol.
Determine the g-moles of methanol in 300.0 kg of the mixture.
The flow rate of methyl acetate in the mixture is to be 100.0 lb-mole/h. What is the mixture flowrate in lbm/h?
Homework Answers
Given 1500g C6H6 (Molecular weight = 78)
kg C6H6 = 1500/1000 = 1.5kg
mol C6H6 = 1500/78 = 19.23 gmol
lbmol C6H6 = 19.23*0.0022 = 0.0424 lbmol
moles of C = 6*moles of C6H6 = 6* 19.23 = 115.38 gmol
moles of H = 6*moles of C6H6 = 6* 19.23 = 115.38 gmol
g of C = 115.38 gmol *12 = 1384.56g
g of H = 115.38 gmol *1 = 115.38g
molecules of C6H6 = 19.23 * 6.023*1023 = 1.1583*1025 molecules
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