Question

Could you please show me how to find the coefficients of the of the curve of the point 1 and point 2 using the exponential function y(x) = be^(mx)

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Point 1 (2.5O, 9.30) Pont 2 2.30, .20)

Answer 1

15:23 y= bema Garing loganhin to base e on both sides . we get log y = logh+ logeme log y= roght me The normal equations are Eyon Atm Ex -(1) {xy = 4x+b -2) 1 z 1 Y=logy | x² lay 8.50 9.86 2.2823 6.25 5.71 2.30 9.20 2.2192 5.1 23 :*:8 | {y=4.5 Extil .54 kay=10.81 / substiluting these values in the normal Equations 4:5= 4 + 4.8 m 10.81 = 4.8A + M-54 m Solong these two equation using elimination method 2 A+ 4.8 bn = 4.5 (3) X 4.8 4 SA +11.54m=10.81 4 x 2 -0.049 = -0.02 m=10.02 = 0.5 +0.041 putting m=0.5 in equation (3) 2 A+ 6.8 80.5)= 9.5 ZA: 2.1 . A = 211 =105, .. A=0.05 m=0.5 but a= logeb . bedrė - 2.8576 y= b.ema. y = 2.5576) 60.5)z : b= 2-8576 m= o.s.