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gnment Score: 30.4% Resources Hint Check Ans cion 22 of 23 > For the titration of 70.0 mL of 0.300 M NH, with 0.500 M HCl at
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Ø 70mL 0, 300M NH3 only (Kb = 1,8x10-5) is li8x10-5= (0,3-2) /2=2.020 2*24 or, x = 2,3238*10-3M = [OH-] pH = 14-pOH = 14+ log

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