Question

wo gaseous pollutants in auto exhaust are CO and NO. An environmental chemist is studying ways to convert them to less harmful gases through a reaction represented by the following equation: 2 Colg) + 2NO(g) - 2002) + N2(0) Han = ? Calculate Han Using the following information: CO(g) + %020) -- C0z) AH-263.0 kJ Nig) 0,1g) - 2 NOG AH = 180.6 kJ O -2048 O-64420 O-7454 O - O -4272

Answer 1

A Horn = 2CO(g) + 2NO(g) + 2co, (g) + Mag] Consider the reaction, colg) + 1 g (g) → Co, (g) AH = -283.0 kJ Multiply the exe by a. 2xĄ Co(g) + ! (9) Co, (g) { AH = 2 x (-283.0*I) 2.00(g) + 0, (9) — 260, (g) SH - - 556 KI Consider the reaction, No (g) + O2(g) + 2NO(9) AH = 180.6 kJ Reverse the rxn, (when a rxn is reversed, the sign of enthalpy change changes also reversed) 2 No (g) - N, (g) + O₂(g) AH = -180.6 kJ How, combine the exne as follows: 2001g) + f (g) → 2CQ (g) AH = - 556 kJ 22 Nolg My (g) + alg) AH = -180.6 kJ 26069) + 2NO(g) → 2.6969) + N,(9) AH = (-556–180.-) 9 SS = -746.6kJ Hence Hence, Arxn is 1-746.6 kell. Η γ και η