Question

Show major steps and formulas involved!!!!!, this is a test review!!!!!

1. Shown here are the graphs for i(t) (given in nA) and v(t) (given in MV). m in $t(ms) t(ms) a. (2 points each) What are the values (with units) of (t) at the times listed below? q(1 ms) = q(4 ms) = 1912 ms) = q(5 ms) = q(3 ms) = 1966 ms) = b. (2 points each) What are the values (with units) of p(t) during the time intervals listed below? p(0 ms <t<1ms) = P(1 ms <t< 2 ms) = P(2 ms <ts 3 ms) = P(3 ms < t < 4 ms) = p(4 ms < 5 ms) (5 ms <t< 6 ms) = c. (4 points) What is the value of the total energy (with units) of w(ty between 0 and 6 ms? Remember that w(t) = Jp(t) dt.

Answer 1

q(t) is given by the area under the I(t) , time curve ,

power = v(t)*i(t)

w(t)=11 micro Jule

Son We Know, darlt) il) = > 9(t) = So, the to tal Charge alt) is given by under the cveof icH&t. the 9(1mo) (5X1) xI0, uomb Chm 1m (mus lo a18 mo) = -(2x1) x 10C tale) a(4m) = -(2x1) x 10C +als) 9 (Sms) = +(4 1) x10e+a(9) ar (6ms) (4 x1) x10c tas) so, to tal cherge.→ a14) =E)+92)+a( 3) +V(9)+(5) (S+5-2-2+9+9) X10ulomb. alt)- 14 pieo Calomb a (2) = 10 pica culomb a (3) = 8 pico Culomb. a(4) = 6 pico culomb a (5) = 10 pico Culobmb a16) = 14 picoculomb (10-1t pice) P(E)=VCt).ice) we know, Mii P (oms<t<Ims) = (5x2) Pi Watt. =lo' mpescta mW p(imsct<2 ms).5x1) miut Watt P( 2msLt<3) = (-2×1) - 2 P mw miett -1o foretnteb. mw P( 3ms <t<9mo)= (-2x5) e mili 20 f . m P( msct <S ms) P(5ms<tL Gms) = (4*5) (4xE3) mili a Watt - -12 Postnt (miu wi To tal enersy wIH befwean siven wIt) = JPL)df by - 5x15_ 2x163 -12X10 Jule Jule = |1M Jule (mien Jule) -1o X1o+ 2ox10. || micoo Jule = l| MJule. wit) = -3 mih