Question

Calculate the grams needed to prepare 1.7 L of sodium hydroxide 3.1 M 210 g оооо О 177 g О 37 g 37 g

Answer 1

Answer:

Step 1: Explanation:

Molarity is defined to be the number of moles of solute divided by volume of solution in liters

Molarity = number of moles of solute / volume of solution ( in L )

Step 1: Calculate the moles of sodium hydroxide (NaOH)

Volume = 1.7 L  

Molarity = 3.1 M = 3.1 mol / L [ unit : M = mol/L]

Since we know ,

molarity = moles of solute / volume of solution in L

=> moles of solute(NaOH) = molarity × volume of solution

moles of solute(NaOH) = 3.1 mol / L × 1.7 L = 5.27 mol

Step 3: Calculation of mass of sodium hydroxide(NaOH)

Now, convert moles to mass by using molar mass

molar mass of sodium hydroxide ( NaOH ) = 39.997 g/mol

we know,  moles = mass / molar mass

=> mass = moles × molar mass

mass = 5.27 mol × 39.997 g /mol ≈ 210 g

hence, the total mass in grams of sodium hydroxide ≈ 210 g ---> option(A)