Homework Answers
Answer 6
LSR (Logical shift right) divides the value by power of 2 where power is equal to shift amount. It happens as value is shifted towards right by inserting 0 from the left side.
LSL (Logical shift left) multiplies the value by power of 2 where power is equal to shift amount. It happens as value is shifted towards left by inserting 0 from the right side.
R0 = 1024 = 0x00000400
R0 = 0000 0000 0000 0000 0000 0100 0000 0000 (In binary)
a) R0 LSR #6
= 0000 0000 0000 0000 0000 0100 0000 0000 >> 6
= 0000 0000 0000 0000 0000 0000 0001 0000
= 0x00000010
= 16 (base-10)
b) R0 LSR #7
= 0000 0000 0000 0000 0000 0100 0000 0000 >> 7
= 0000 0000 0000 0000 0000 0000 0000 1000
= 0x00000008
= 8 (base-10)
c) R0 LSR #8
= 0000 0000 0000 0000 0000 0100 0000 0000 >> 8
= 0000 0000 0000 0000 0000 0000 0000 0100
= 0x00000004
= 4 (base-10)
d) R0 LSR #9
= 0000 0000 0000 0000 0000 0100 0000 0000 >> 9
= 0000 0000 0000 0000 0000 0000 0000 0010
= 0x00000002
= 2 (base-10)
e) R0 LSR #10
= 0000 0000 0000 0000 0000 0100 0000 0000 >> 10
= 0000 0000 0000 0000 0000 0000 0000 0001
= 0x00000001
= 1 (base-10)
f) R0 LSL #21
= 0000 0000 0000 0000 0000 0100 0000 0000 << 21
= 1000 0000 0000 0000 0000 0000 0000 0000
= 0x80000000
= 2147483648 (base-10 unsigned)
g) R0 LSL #22
= 0000 0000 0000 0000 0000 0100 0000 0000 << 22
= 0000 0000 0000 0000 0000 0000 0000 0000
= 0x00000000
= 0 (base-10)
h) R0 LSL #23
= 0000 0000 0000 0000 0000 0100 0000 0000 << 23
= 0000 0000 0000 0000 0000 0000 0000 0000
= 0x00000000
= 0 (base-10)
i) R0 ASR #8
Arithmetic shift right inserts bit from the left same as sign bit
= 0000 0000 0000 0000 0000 0100 0000 0000 >> 8
= 0000 0000 0000 0000 0000 0000 0000 0100
= 0x00000004
= 4 (base-10)
Now given value of R0 is as below.
R0 = 2952790016 = 0xB0000000
R0 = 1011 0000 0000 0000 0000 0000 0000 0000
j) R0 LSL #2
= 1011 0000 0000 0000 0000 0000 0000 0000 << 2
= 1100 0000 0000 0000 0000 0000 0000 0000
= 0xC0000000
= 3221225472 (base-10)
k) R0 LSR #2
= 1011 0000 0000 0000 0000 0000 0000 0000 >> 2
= 0010 1100 0000 0000 0000 0000 0000 0000
= 0x2C000000
= 738197504 (base-10)
l) R0 ASR #2
= 1011 0000 0000 0000 0000 0000 0000 0000 >> 2
= 1110 1100 0000 0000 0000 0000 0000 0000 (Sign bit copied)
= 0xEC000000
= 3959422976 (base-10)
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