Question

Up ompound beam is subjected to a uniform dead load of 200 lb/ft and a uniform live load of 150 lb/ft. ermine (a) the maximum negative moment these loads develop at A, and (b) the maximum positive Shear these loads develop at D. Assume B is a hinge. El = constant. S: Live loads may be placed on any segment on the beam to maximize a function. Also, take advantage of the influence lines. There is load no point A 5 ft 5 ft

Answer 1

А в р 7 K 55 a) max -ve moment @ A b) max the Sheay @ D 2011: 5/10 = 1/2 5/10 = 1/2 ILD for tre shear @D. dead load acting on beam - 200 lb/ft dl= Area of ILD * Load o = 0 $ the and -ve area sum} live load can be placed anywhere, to get max shear place live load in span DC 150 2. Total load = Area of ILD* load 5x 5x 4 * 150 st = 187.5 KN

(bj ILD for BM @ A A10=1 V 5 due to dead loads = act along the whole stu cture = Area * Ceo load 14 15 * 5 * 200 = 7500 Ubaft

2. due to live loads. x 15x5 x 150 = place it on the whole structure. 2 = 5625 lb-st Total -ve moment = 7500+5625 - 13,125 lb-st.