Question

Please Do Question 2 :

1. (20 points) In a thundercloud, there may be electric charges of +50.0 C near the top of the cloud and -100.0C near the bottom of the cloud. These charges are separated by 2.00 km. What is the electric force on the top charge? 2. (20 points) Three point charges are arranged as shown below. Find (a) the magnitude and (b) direction of the electric force on the particle at the original. 6.00 nC 5.00 nC0.300 m 0.100 m -3.00 nC

Answer 1

F_21 = F by 2 on 1, F_31 = F by 3 on L K(6 times 5) times 10^-18/(.3) ^2 K (3 times 5) /(.1) times 10^-18 = > F_net = squareroot (k times 10^-18) ^2 {(30) ^2/(.3) ^2 + (15) ^2/(.1) ^2} = (k times 10^-18) squareroot 10000 + 22500 = 180.2 times 5 times 10^5 times 10^-18 = 1622.4 times 10^-9 in southwest.