
7) f(x) = 3 sec(4x + 3 a. Amplitud: b. Periodo: c. Despl. Horizontal: d. Asintotas:...
Compute f (x) for f(x)=tan(e-3x + sin 4x + 2) a. f(x)=(-3e-3x + 4cos 4x) sec?(e-3x + sin 4x+2) b. None of the other answers oc f'(x) = sec?(-e-3x + 4cos 4x) d. f'(x) =(e-3x + sin 4x) sec?(e-3x + sin 4x+1)
integrate. state du and u
a) tan(4x sec (4x)dr dx r +1 b) dx x +1 c) csc (3xax
a) tan(4x sec (4x)dr dx r +1 b) dx x +1 c) csc (3xax
cos x + cos 2x cos 3x+ cos 4x 0, is a) 3 c) 7 b) 5 d) 9 Let tan-1 y = tan, + tan-1 ( tan-1 (-Zr where |x| < + v/3 Then a value of y is 1-3z2 1-32 1 + 3z2 1+3 If the angles of elevation of the top of a tower from three collinear points A, B and C, on a line leading to tower, are 300 450 and 60 respectively then the ratio,...
1) For each of the following functions, determine: the period the amplitude, if any one pair of successive vertical asymptotes (if there are any at all) the phase (horizontal) shift, saying by how many units and whether to the right or to the left 3 cos 4x a) b) cot (x-) c) sec (x+ 1) d) 1+3 tan mx
1) For each of the following functions, determine: the period the amplitude, if any one pair of successive vertical asymptotes (if...
Verify that the equation is an identity. sec *x-tan 4x = 2 sec 2-1 To verify the identity, start with the more complicated side and transform it to look like the other side. Choose the correct transformations and transfer sec 4x-tan 4x = sec?x + tan x) Factor the difference of two squares. O(secx+ tanºx) (Type an exact answer in simplified form.) Choose an identity, and use it to transform tan-x. Then simplify. = 2 secx-1 7
Differentiate. #’s 1,3, and 5 please
5.S LALT 1-16 Differentiate 2. f(x) = x cos x + 2 tanx 1. f(x) = x2 sin x 3. f(x)ecos x 2 sec x 4. y csC x 6. g(0)= e'(tan 0 e) 5. y = sec 0 tan 0 cot t
5.S LALT 1-16 Differentiate 2. f(x) = x cos x + 2 tanx 1. f(x) = x2 sin x 3. f(x)ecos x 2 sec x 4. y csC x 6. g(0)=...
Find dy/dx of the next relations
Sol: y ylx 1 1-Cx C 2) 1+cx y' (1+cx1-cx a+bx ab 3) y= In Va-bx y's a2-b'x 4) y= atan (t); x = bcor (t) 6) x+2 7) y = 2v+ 45; donde v 52., W sec X 8)4x+3 8xy+e -e+ 8cos[tan(y)] = 0 arcsec (); x = elog2 (Int) 9) y 10) y sen[tan(x )] 11) y = cos[sen' (x)] cot + 4 12) y 13) y = [sec'(secx))P 14) y [Beae...
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717 7. 777 COS 8. cot sec 370 311 10. sec 9. tan
Directions: In 7-10, determine the rectangular equation given its polar form. [7] = 9 A. x + y2 = 3 B. x + y2 = 9 C. x² + y2 = 81 D. x + y = 9 [8] r = - 179csce A. X = -179 B. x = 179 c. y = -179 D. y = 179 E. none of these [9] @ = 13 A. y =- 13 3 x B.y = c. y = -13 D....
Stan®x.secs x dx tanºx a) 2 tan' x tanºx + +c 5 sec b) 2 sec + secx 5 + c 9 sec? sec5 x c) + c d) None of the above