(Q1)
(a)
n = 12
x-bar = 3250
s = 31.6227766
% = 95
Standard Error, SE = σ/√n = 31.6227766016838 /√12 = 9.128709292
z- score = 1.959963985
Width of the confidence interval = z * SE = 1.95996398454005 * 9.12870929175277 = 17.89194144
Lower Limit of the confidence interval = x-bar - width = 3250 - 17.8919414371716 = 3232.108059
Upper Limit of the confidence interval = x-bar + width = 3250 + 17.8919414371716 = 3267.891941
The 95% confidence interval is [3232.11 psi, 3267.89 psi]
(b)
n = 12
x-bar = 3250
s = 31.6227766
% = 99
Standard Error, SE = σ/√n = 31.6227766016838 /√12 = 9.128709292
z- score = 2.575829304
Width of the confidence interval = z * SE = 2.57582930354892 * 9.12870929175277 = 23.5139969
Lower Limit of the confidence interval = x-bar - width = 3250 - 23.513996897276 = 3226.486003
Upper Limit of the confidence interval = x-bar + width = 3250 + 23.513996897276 = 3273.513997
The 99% confidence interval is [3226.47 psi, 3273.51 psi]
The 99% confidence interval is wider than the 95% confidence interval
(c)
For 99% confidence, z = 2.5758
E = 15
Sample size N = (z * σ/E)^2 = (2.5758 * √1000 /15)^2 = 30
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ters, Statistical Intervals for a Single Sample Prok cm : An engineer is analying the compressive...
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Current Attempt in Progress Construct 90%, 95%, and 99% confidence intervals to estimate from the following data. State the point estimate. Assume the data come from a normally distributed population 12.4 11.6 11.9 12.9 12.5 11.4 120 11.7 118 12.4 Appendix A Statistical Tables (Round the intermediate values to 4 decimal places. Round your answers to 2 decimal places.) SUS 90% confidence interval: SM 95% confidence interval: sus 99% confidence interval: The point estimate is
Construct 90%, 95%, and 99% confidence intervals to estimate
μ from the following data. State the point estimate.
Assume the data come from a normally distributed
population.
12.1
11.6
11.9
12.3
12.5
11.4
12.0
11.7
11.8
12.1
Appendix A Statistical Tables
(Round the intermediate values to 4 decimal places.
Round your answers to 2 decimal places.)
90% confidence interval:
≤ μ ≤
95% confidence interval:
≤ μ ≤
99% confidence interval:
≤ μ ≤
The point estimate is
.
Pr。Ыет 12. An engineer who is studying the tensile strength of a steel alloy intended for use in golf club shafts knows that tensile strength is approximately normally distributed. A random sample of 12 specimens has a mean tensile strength of 3250 psi and a sample standard deviation of 8-60 psi. a) Test the hypothesis that mean strength is 3500 psi. Use α-001. b) What is the smallest level of significance at which you coulji be willing to reject the...