Question

a 100W light bulb connected to a 12.0 V source experiences a voltage surge that produces 14.0V for a moment. By what percentage does its power output increase? Assume its resistance does not change.

Answer 1

Answer 2

let the resistance of bulb be R.

then power=voltage^2/R

so R=1.44 ohms

so when voltage=14 volts

power=14^2/R=136.11 W

so % increase=(136.11-100)/100=36.11%

Answer 3

P = V^2/R

P is propotional to V^2

(14/12)^2 x 100

136.11 %

increae = 136.11 -100 = 36.11 %