Question

1439-140 Fund Mac westion 2 bad mby Im that weighs 25 N slides down an inclined ame(slope 20%) with a velocity of 2.0 m/s. The board is rated from the ramp by a thin film of oil with a viscosity of 0.05 Nm Neelecting edge effects, solve the following questions: 1) Draw the free body diagram of the board and show all the forces acting on this board. 2) In case of equilibrium (constant velocity), what is the shear force? T= ma 0.05x 2 x T= 0.1 3) Calculate the space between the board and the ramp. Hint: With a linear velocity distribution, can everywhere be expressed as space between the board and the ramp. where AV is the velocity of the board, and

Answer 1

Pue-2 Square Board Giren A = 1X1 = 1m2 weight W = 25kN Vsliding = 2mst ly = sepacated = ? (find) angle of slope o: 200 distance lois = 005 NS/m2. forset Fy = ? (find), @ free body diagram : film by til thitness fBD : Normal V2m A = im W 25 KN 20 = 20 assin 2 2 5005 20 W=25 Hence in this two force acting mainly olveight force & Shear force so this FBD with all the forces acting on this board. find shear force value : iş Fy - 25 Sin 20 = 8.55 KN Shear force 1 force acting a plate opposite to its motion find space b/w boas Hoe ramp. now Ea e dy z wyo (25 (days ago V) А у so = 4 Hence y = 4V A = 0.05 X 2 X 1 = -0.01169 x16?m 8.55 X103 Hence ya 11.69 mm. so space blw them in 11.69 mm. so ay @, D {@ sub question is solved & determined required values from given data. ie., Shear fy = 8.55 KN 4 y = 11.69 mm. force