Question

Given that the sodium bisulfide solution in this experiment is 0.070 M, calculate the number of moles of sodium bisulfide present in Trial A. Question 7 options:

0.35

350

0.00035

0.0007

Answer 1

SOLUTION:

Number of moles of bisulphite (n) = Molarity(M) X volume(V). ======1)

Since you have not given the Volume so here we show you the procedure how to calculate it. Insert the correct volume in the final equation (given below) to get the number of moles

n = M X V. ======2)

M = molarity ; V = volume in liters.

If volume is not given in liters convert the volume to liters as:

For example if volume is in mL units convert mL to L as:

1mL = 1 / 1000 = 0.001L

Thus 1mL = 0.001L

2 mL = 0.001X 2 = 0.002L

3mL = 0.001 X 3 = 0.003L

Similarly y mL = 0.001 X y L