Question

2) A particle moves in the x-y plane. Known information about the particle’s motion is given below: ???? = 150?? ft/sec. and at time t = 0, x = 6 ft ?? =5??3+50?? ft a) Derive, as functions of time, the position (x), acceleration (ax), velocity (vy), and acceleration (ay). b) Using your functions, calculate, at time t = 0.25 seconds, the total magnitude of velocity ?? of the particle and the angle ????the velocity vector makes with the x-axis. c) For the same time (t = 0.25 sec.), calculate the total magnitude of acceleration ??⃑ of the particle and the angle ???? the acceleration vector makes with the x-axis.

Answer 1

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IP Un = 150 f fe /sec yet). 5tot ft and at to ;x=tlt - Vr = de San - vedt => X(t) = 6 + 75th ft - Chn eV = 150 ft/sec2 of Vy=dy = 156 710 ft/sec2 ; ay a dry - 30t tefsee? Timor Vat at t= Yusec Vx = 37.5 felfec & Vy = 10.9375 ft/sec 8 v= Justry? = 39.0625 ft/sec os tomboy) = 16.26° © at t=1/4 sec ; ay = 150 ft/sec? ; ay = 7.5 ft/sec? a- Joštay = 150.187393 ft fer - tonirane) = 2.86 24° - 2.86: RELE