
I need help finding the balanced equation for the above reaction to calculate the limiting reagent and percent yield. If someone could tell me the common name of the product that would also be helpful. Thank you

I need help finding the balanced equation for the above reaction to calculate the limiting reagent...
can someone help please!!!
REPORT FORM: REGIOSELECTIVE BROMINATION OF ACETANILIDE Balanced Equation(s) for Main Reaction(s): Brz Hjc Coche 4 И В Balanced Equation(s) for Important Side Reactions): compound MW mg or ml mmol acetanilide B5.17 95 mg 6. 25 ml bromine 159.22 p-bromoacetanilide 214.07 Indicate the limiting reagent with an asterisk (*). Product Observed melting point range: 160.0.4480 Literature melting point range:167.169 °C Molecular weight of product: 214.07 Theoretical yield: Experimental yield: g Percent yield: 95 %
Trying to calculate Theoretical yield but I think I need the
moles of the limiting reagent. I thought I needed density if only
the limiting reagent was in mL. Need help. Thanks in
advance
Synthesized 2-chloro- Zmethyl butane starting with 10 mb of 2-chloro- 2 methyl butanol. The reaction yielded a product of 9.4312 g Calculate percent yield. Molar Mass of 2-chloro-2 methyl butanol. 10ml 122.59 g/mol C5H, CIO Molar Mass of 2-chloro-2 methyl butane 106.59 g/mol Cs Huch
6. (25 pts) (a) Calculate the theoretical yield, (b) limiting reagent, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 60 mmol of aqueous hydrobromic acid and you obtained 4.1g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:
Question text A limiting reagent is Choose...consumed completelyleft over in excess during a chemical reaction, and it Choose...decreasesincreases the possible amount of product that can be formed. Question 2 Not yet answered Points out of 1 Flag question Question text A student used 7.15 g of CaCl2 and 9.25 g of K2CO3 to make CaCO3. The reaction is: K2CO3(aq) + CaCl2(aq) = CaCO3(s) + 2KCl(aq). Based on the masses of the two reactants given, the limiting reagent is Choose...CaCl2K2CO3 ....
I
need help with problem 4 and 5.
Calculations 1. Show the correct, balanced, molecular formula equation for the reaction you performed C7H703+C4H603 -->CH8O4+C2H402 2. Determine the limiting reactant in your reaction; is it salicylic acid or acetic anhydride? Show your work. Limiting reagent is salicylic acid 2.0/138.12g/mol =0.0145mal number of moles of salicylic acid. 1.086/ml -mass/5.0mL Massa 5.4 5.4/102,09g/mol =0.053 mol of acetic anhydride 0.0529-0.0145-0.0384 moles unreacted moles of acetic anhydride 3. What is the theoretical yield of acetylsalicylic...
Consider the following UNBALANCED equation: Na(s) + Cl2(g) -> NaCl(s). a.) Calculate the limiting reagent when 55.0 g of react with 67.2 g of Cl2. (Show all work, and clearly state which is the limiting reagent.) b.) What is the theoretical yield, in grams, of NaCl? c.) If 105g of NaCl is produced from the reaction, what is the percent yield of NaCl?
what is my limiting reagent, theoretical yield
calculated from moles , and % yield for the synthesis of banana
oil?
Isoamyl acetate (banana oil) is made by the acid
catalyzed reaction (fischer esterification) between isoamyl alcohol
and acetic acid. sulfuric acid was used as the catalyst for the
fast conversion of product from starting alcohol and acid. the
catalyst only affects the rate of the reaction not the extent of
the reaction.
here is the data from lab:
here is...
Calculate the theoretical yield and percent yield. What is the limiting reagent? Reaction: Aniline to Acetanilide in acetic anhydride, HCl, and NaOAc 5 g of aniline 4.5 mL HCl 5.32 g sodium acetate 6.60 g acetic anhydride 4.33 g of acetanilide (product)
i need help calculating the theoretical yield and limiting
reagent for this experiment: biodiesel production using
base-catalyzed trans-esterification. assume the product is 100%
methyl oleate.
we used a 6:1 mole ratio of methanol in the lab instead of 3:1
given in the equation. and we used a 1% by mass catalyst load for
the sodium methoxide catalyst
mass of total product: 28.91 g
OH o R- OH OM R + 3CH₂OH Naome 3 R40CM + catalyst R 커 (methanol) (methyl...
i need to calculate the theortetical yield by finding the
limiting reactant of the experiment by converting reactants to
product, then calculate the percent yield using the limiting
reactant
-in my experiment the amout of crystals i obtained was 1.232 g
(watch glass + filter paper = 31.228 g and watch glass, filter
paper, + crystals = 32.460 g)
REACTION SCHEME H сно, ОН- ОСH, CH panisaldehyde acetophenone Molar Mass: 120.15g/mol Molar Mass: 136.15g/mol Molar Mass: 239.30g/mol Density: 1.119g/mL Density:...