answer to this question is (B)
missing - *cp-- and *++cp
in first part cp points to third character of array (that is C), and condition is cp>=c , so this can be false only when cp becomes less than c which is only possible when cp is decreasing , (*cp --) this prints *cp charcter to which cp points and -- decreases it by 1 as it now points to Band furthur more it will point to A and when it becomes less than address value pointed by c it will come out of loop.
in second part , cp = c+ 3, it means it points to D, output is EFG which is only possible when cp value is incremented first like *++cp,which implies that ++ increases the pointer value to next as it points to E now and so on untill it reaches condition c+6 .
i need it quick teacher 28. Consider the code int k; char c = "ABCDEFG"; char...
int *fun(int *p) { while(*p >= 0) p++; return p; } void main() { I int *a; int v[8]={1,2,3,-4,5,6,7,8); q = fun(); printf("%d", _Missing_1_); printf("%d", -_Missing_2_); } However, part of the code is missing (indicated by). The code is supposed to give the output -46 What can the missing parts be? DS (4 Points) Missing 1: * Missing 2: [2] Missing_1: V[4] Missing 2: [2] Missing 1: *q Missing 2: q[1] Missing 1: *(q+1) Missing 2: *(q+2)
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