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28. Consider the code int k; char c = ABCDEFG; char *cp: for(cp = C+2; cp >= c.) printf(%c, Missing 1); printf(\n); for
ĐI II 1 ). for(cp = C+3; cp <= C+6:) printf(%c, Missing_2_); However, part of the code is missing (indicated by output ). T
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answer to this question is (B)

missing - *cp-- and *++cp

in first part cp points to third character of array (that is C), and condition is cp>=c , so this can be false only when cp becomes less than c which is only possible when cp is decreasing , (*cp --) this prints *cp charcter to which cp points and -- decreases it by 1 as it now points to Band furthur more it will point to A and when it becomes less than address value pointed by c it will come out of loop.

in second part , cp = c+ 3, it means it points to D, output is EFG which is only possible when cp value is incremented first like *++cp,which implies that ++ increases the pointer value to next as it points to E now and so on untill it reaches condition c+6 .

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