are my answers correct? Consider the following data from two independent samples with equal population variances....
Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed. x overbar 1 equals= 37.1 x overbar 2 equals= 32.8 s 1 equals= 8.68 S2 equals= 9.59 N1 equals= 15 N2 equals= 16 The 99% confidence interval is ( )(. ).
cnsider the following data rom wo populations are normally distributed. dependent samples th equal population var ances on struct a 9 % con der ce te val o es mate he dif rn ein po ulation means. Assume the popula on variances are equal and at the X1-36.42 S1-8.8 n1 #18 82 9.1 n2 19 ge 1 Click here to see the t distribution table page 2 The 90% confidence interval is( Round to two decimal places as needed.) DD
onsider the following data rom t o independent samples h equal population variances onstruct a 98% con ce interval to estimate the difference in population means ss me he population variances are equal and that the populations x137.1 S1 = 8.8 s2 = 9.2 The 98% confidence interval is (Round to two decimal places as needed.)
Suppose we had the following summary statistics from two different, independent populations, both with variances equal to σ. Population 1: ¯x1= 126, s1= 8.062, n1= 5 Population 2: ¯x2= 162.75, s2 = 3.5, n2 = 4 We want to find a 99% confidence interval for μ2−μ1. To do this, answer the below questions. Suppose we had the following summary statistics from two different, independent populations, both with variances equal to o: 1. Population 1: Ti = 126, $i = 8.062,...
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1=51, n2=46, x¯1=57.8, x¯2=75.3, s1=5.2 s2=11 Find a 94.5% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances. Confidence Interval =
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1=39, x¯1=57, s1=5.8 n2=50, x¯2=74.2 ,s2=10 Find a 98% confidence interval for the difference μ1−μ2 of the means, assuming equal population variances. Confidence Interval =
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1= 37 n2=44 x-bar1= 58.6 x-bar2= 73.8 s1=5.4 s2=10.6 Find a 97% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances.
Consider the following results for independent random samples taken from two populations. Sample 1 Sample 2 n1= 20 n2 = 40 x1= 22.1 x2= 20.6 s1= 2.9 s2 = 4.3 a. What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down)? c. At 95% confidence, what is the margin of error (to 1 decimal)? d. What is the 95% confidence interval...
Given two independent random samples with the following results: n1=16x‾1=157s1=25 n2=8x‾2=192s2=15 Use this data to find the 99% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Step 3 of 3 : Construct the 99% confidence interval. Round your answers to the nearest whole number.
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 90% confidence interval estimate for the difference between the two population means. n1 = 17 x1 44 n2 13 x2 = 49 The 90% confidence interval is s(uI-12) (Round to two decimal places as needed.) «D