A regular hexagon shaped wire loop with a side length of a = 41.0 cm carries an electric current of I = 12.0 A as shown in the figure.
Determine the size of the magnetic field at point Q, one of the vertices of the hexagon.
Homework Answers
given
a = 41.0 cm
= 0.41 m
I = 12.0 A
r = ( a/2 ) / tan30
r = ( 0.41/2 ) / tan30
r = 0.355 m
using equation magnetic field due to the rectangular of the hexagon is
B = n 
o i sin (
/n ) / 2 r
B = 6 X 4 X 3.14 X 10-7 X 12 X sin ( /6 ) / 2 X 3.14
X 0.355
B = 2.028 X 10-5 T
the size of the magnetic field at point Q, one of the vertices of the hexagon is B = 2.028 X 10-5 T
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