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A sample of 536 mL of chlorine at a pressure of 754 mm Hg is placed in a container under a pressure of 744 mm Hg. The tempera
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Answer #1

At Constant Temperature ,

P_{1}V_{1} = P_{2}V_{2}

P1 = 754 mm of Hg = 0.992 atm

V1 = 536 mL = 0.536 L

P2 = 744 mm of Hg = 0.979 atm

V2 = To be determined

P1V1 = P2V2

V2 = P1V1 / P2 = 0.992 atm * 0.536 L / 0.979 atm = 0.543 L

The Volume of Container is 0.543 L

The Correct Option is (ii)

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