Question

Find the equation of the circle of radius 3 centered at:

a) (0, 0)

b) (5, 6)

c)  (−5, −6)

d) (0, 3)

e) (0, −3)

f) (3, 0)

Please show how you did them and which equations you used

Answer 1

Formulae: - = > The equation of circle of radius 'R' and center at (x_1, y_1) is (x - x_1)^2 + (y - y_1)^2 = R^2 Given Radius = 3 center = (0,0) equation of the circle is (x - 0)^2 + (y - 0)^2 = 3^2 x^2 + y^2 = 9 center = (5,6) equation of the circle is (x - 5)^2 + (y - 6)^2 = 3^2 center = (-5,-6) equation of the circle is (x - (-5))^2 + (y - (-6))^2 = 3^2 (x + 5)^2 + (y + 6)^2 = 3^2 center = (0,3) equation of the circle is (x - 0)^2 + (y - 3)^2 = 3^2 x^2 + (y - 3)^@ = 9 center = (0,-3) equation of the circle is (x - 0)^2 + (y- (- 3))^2 = 3^2 x^2 + (y + 3)^2 = 9 center = (3,0) equation of the circle is (x - 3)^2 + (y - 0)^2 = 3^2 (x - 3)^2 + y^2 = 9