#include<stdio.h> voidmain() { int i = 0; while (i < 10) { printf("i is currently %d\n",...
#include<stdio.h>
voidmain() {
int i = 0;
while (i < 10) {
printf("i is currently %d\n", i);
++i;
}
}
Compile the code file using the command line. Copy the assembly code for just the _main sub-routineand paste it as your answer to this question and highlight the lines which corrospond to the ++i; statement from the source code.
Homework Answers
answer:-i am saving this file as ex1.c then execute the command gcc -S ex1.c..then we will get a file named as ex1.s which contains the assembly code for the above code..so the assembly code for the main function of the above program is:-
main:
.LFB0:
.cfi_startproc
pushl %ebp
.cfi_def_cfa_offset 8
.cfi_offset 5, -8
movl %esp, %ebp
.cfi_def_cfa_register 5
andl $-16, %esp
subl $32, %esp
movl $0, 28(%esp)
jmp .L2
.L3:
movl 28(%esp), %eax
movl %eax, 4(%esp)
movl $.LC0, (%esp)
call printf
addl $1, 28(%esp) // this line corresponds to the ++i statement
.L2:
cmpl $9, 28(%esp)
jle .L3
leave
.cfi_restore 5
.cfi_def_cfa 4, 4
ret
.cfi_endproc
note:-i have commented the line. which corresponds to ++i ststement
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task1 code：
#include <stdio.h>
#include <sys/time.h>
int main()
{
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of program
gettimeofday(&start,0);
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