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Consider the reaction Fe203(s)+3H2()2Fe(s)+3H20( Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.59 moles of Fe203(s) react at standard conditions AS suroundings J/K 2 more group attempts remaining
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Answer #1

From t standard thrmodynnmic dan we have to cakeuat 十3 Hrn hel change per DHSysニ9.74 KJ7mol ( absorb hat Endothermc, ie systm3) Refer al 298 K AS sys -1766: 23/κ. = &MTxn for 2, 20 mole 42 2 ie H 298K AS 子23.gb.丁/k sum = 6) S

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please i need ALL of the answers!! PLEASEEEE Consider the reaction Fe203(s)+3H2()2Fe(s)+3H20( Using standard thermodynamic data...
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