Given that
Volume = 430.0 ml
Molarity = 3.6 M
Number of moles = molarity * volume in L
= 3.6 *430.0 /1000
= 1.548 Moles
1 mole = 1000 mille moles
1.548 Moles *1000 mmoles /1 mole = 1548 mmoles
A chemist adds 430.0 mL of a 3.6M potassium iodide (KI) solution to a reaction flask....
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