Question

A chemist adds 430.0 mL of a 3.6M potassium iodide (KI) solution to a reaction flask. Calculate the millimoles of potassium iodide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

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Answer #1

Given that

Volume = 430.0 ml

Molarity = 3.6 M

Number of moles = molarity * volume in L

= 3.6 *430.0 /1000

= 1.548 Moles

1 mole = 1000 mille moles

1.548 Moles *1000 mmoles /1 mole = 1548 mmoles

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