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how long should a closed tube in air be such that it's fundamental frequency is 250Hz?...

how long should a closed tube in air be such that it's fundamental frequency is 250Hz? use V=343m/sec (B) what is the frequency of its next possible mode ?

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Answer #1

Part\: A:

For\: a\: closed\: tube:

f_n=n\: f_0\: \: \: \: \: ;\: \: \: \: n=1.3.5...

The\: fundamental\: frequency\: is\: when\: n=1.

The\: long\: is:

L=\frac{\lambda }{4}=\frac{\frac{v}{f_1}}{4}=\frac{v}{4f_1}=\frac{343\: \frac{m}{s}}{4\left ( 250\: Hz \right )}={\color{Blue} 0.343\: m}

Part\: B:

The\: next\: possible\: mode\: is\: when\: n=3,\: so:

f_3=3\: f_0=3\left ( 250\: Hz \right )={\color{Blue} 750\: Hz}

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