A 200 N force pulls a 100 N box on a frictionless table. The acceleration of...

Question

Question

A 200 N force pulls a 100 N box on a frictionless table. The acceleration of the block is ___ m/s/s

If instead, a 200 N weight was hung on the string then the acceleration would be ___ m/s/s

science physics

Answer 1

Answer #1

Net force acting on the block when it is on the table = 200N

acceleartion of the block = F/m = F/(W/g)

where W is the weight of the block

a = 200/(100/9.8)

a = 19.6 m/s2

when the block is hung from the string

net force = weight + F(applied)

F(net) = 100 + 200 = 300N

acceleration when the block is hung with a string = 300/(100/9.8)

= 29.4 m/s2

Answer 2

Similar Homework Help Questions

Question 1 A 10 kg block rests on a flat frictionless table. A force of 200...

Question 1 A 10 kg block rests on a flat frictionless table. A force of 200 N, F2 = 100 N are applied to the box. Also, F3 = 501 on a flat frictionless table. A force of F applied to the box. Also, F = 50 N is applied at an angle of 0 = 30°. These forces cause the block to slide a distance x = 5 m. Calculate (a) the total work done by the forces. (b)...
1. M, a solid cylinder (M=2.03kg, R=0.137m) pivots on a thin, fixed, frictionless bearing. A string...

1. M, a solid cylinder (M=2.03kg, R=0.137m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.670kg mass, i.e., F = 6.573N. Calculate the angular acceleration of the cylinder. (Answer in rad/s2.) 2. If instead of the force F an actual mass m = 0.670kg is hung from the string, find the angular acceleration of the cylinder. Use units of "rad/(s*s) 1. M, a...
A box weighs 60 N and is sitting on a horizontal frictionless floor. A 100 N...

A box weighs 60 N and is sitting on a horizontal frictionless floor. A 100 N force pulls the box at an angle 30 degrees above the horizontal. What is the normal force of the box?

M, a solid cylinder (M=2.23 kg, R=0.131 m) pivots on a thin, fixed, frictionless bearing. A...

M, a solid cylinder (M=2.23 kg, R=0.131 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.870 kg mass, i.e., F = 8.535 N. Calculate the angular acceleration of the cylinder. 5.84×101 rad/s^2 If instead of the force F an actual mass m = 0.870 kg is hung from the string, find the angular acceleration of the cylinder. How far does m travel...
M, a solid cylinder (M=1.79 kg, R=0.119 m) pivots on a thin, fixed, frictionless bearing. A...

M, a solid cylinder (M=1.79 kg, R=0.119 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.630 kg mass, i.e., F = 6.180 N. a) Calculate the angular acceleration of the cylinder. b) If instead of the force F an actual mass m = 0.630 kg is hung from the string, find the angular acceleration of the cylinder. c) How far does m...
a 12 kg box sits on a horizontal table. a string with tension 30.4 N pulls...

a 12 kg box sits on a horizontal table. a string with tension 30.4 N pulls on the box to the right, but static friction between the box and the table prevents the box from moving. the coefficient of static friction between the box and table is 0.43. what is the magnitude of the static friction force on the box?

A 12.1 kg box sits on a horizontal table. A string with tension 24.9 N pulls...

A 12.1 kg box sits on a horizontal table. A string with tension 24.9 N pulls on the box to the right, but static friction between the box and the table prevents the box from moving. The coefficient of static friction between the box and the table is 0.35. What is the magnitude of the static friction force on the box?
M, a solid cylinder (M=2.27 kg, R=0.127 m) pivots on a thin, fixed, frictionless bearing. A...

M, a solid cylinder (M=2.27 kg, R=0.127 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.770 kg mass, i.e., F = 7.554 N. I know the answers to A and B, but I need help with C and D A) Calculate the angular acceleration of the cylinder. (ANSWER: 52.4rad/s^2) B) If instead of the force F an actual mass m = 0.770...
A boy pulls a box of mass 30 kg with a force of 25 N in...

A boy pulls a box of mass 30 kg with a force of 25 N in the direction shown in 6Fig. 4.33. If the friction coefficient is u = 0.2. What is the normal force exerted on the box by the ground, what is the friction force and what is the acceleration of the box?

A box with mass M is pulled across a frictionless surface with a constant force F...

A box with mass M is pulled across a frictionless surface with a constant force F as shown below. 13) What is horizontal acceleration of the box? Mg OF F/M OM F/g 14) What is the normal force on the box? Mg OF F/M ом F/g 15) After the block is accelerated for 5 s, the force stops pulling on the box. What happens? The block comes to rest. The block continues in the same direction with a constant speed....