An athlete of average size is hanging from the end of a 20 m long rope, which has a mass of 4 kg and is attached to a hook in the ceiling of a gym. If the athlete makes a sudden movement at the end of the rope, estimate how long it will take the disturbance to reach the hook.
The tension in the rope would be necessary. Supposing it is the weight of the athlete, we have:
\(\mathrm{T}=\mathrm{W}=\mathrm{m}_{\mathrm{a}} \mathrm{g}\) (consider a mass of \(70 \mathrm{~kg}\) )
The speed of the transversal wave has the formula:
\(v_{t}=\sqrt{\frac{T}{\mu}}=\sqrt{\frac{m_{a} g l}{m_{r}}} \approx 58.6 \mathrm{~m} / \mathrm{s}\)
miu=mass of unit length of the rope
\(\mathrm{m}_{\mathrm{r}}=\) mass of the rope
The time to reach the hook: \(\mathrm{t}=\mathrm{l} / \mathrm{v}_{\mathrm{t}} \sim 0.34 \mathrm{~s}\).
The numerical result might be different, but the tension or the mass of the athlete is necessary.
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Question 8 please-show all work
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