A) 5.1 B) 5.4 C) 5.7 09: A conducting solid sphere of radius R=12cm creates an...

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science physics

Answer 1

Answer #1

field due to charged sphere

E = k q / r^2

220* 1000 = 9* 10^9 q / 0.24^2

q = 1.408* 10^-6 C

now, surface charge density

sigma = q / ( 4 pi R^2) = 7.788 uC/m^2

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Answer 2

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