the number of moles in Co2 is
n = m/M = 6 g/44g /mol = 0.136 mol
Apply ideal gas equation
P1 V1 = nRT1
P1 = nRT1/V1
=0.136(8.314)(273 k)/5000 cm^3 ( 1 m/100 cm)^3
=61901.5 Pa ( atm/1.01325* 10^5 pa )
=0.61 atm
(b)
P1 V1 = P2 V2
V2 = P1 V1/P2
=5000(0.61)/2.8
=1090.929 cm^3
under isobaric compression
T2 V3 = T3 V2
T3 = V3 T2/V2
=273 (700 cm^3)/1090.929 cm^3
= 175.1717 K
in centigrade
T3 = 175.171 K - 273
=-97.82 C
rounding to two significant
T3 = -98 C
CHW13 Ch. 18 (Extra Credit HW) 11 of 11 4 Problem 18.64 6 g of dry...
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need help figuring out #5.35, 5.37, 5.45, 5.57, and 5.71
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