Today, the Moon’s orbit around
Earth has a semi-major axis of a=384,400 km and an orbital period
of 27.32166 days.
a. The Moon slowly moves outward due to tidal braking of the Earth’s rotation, and at some future date the Moon will have an orbital period of 47 days. Compute the semi-major axis of the Moon’s orbit at this future date (express your answer in kilometers).
semi-major axis = 5.5*10^5 km
b. Today, the Moon has an angular diameter of about 0.5° as seen from Earth. When the Moon has an orbital period of 47 days, what will its angular size be? Can there be total solar eclipses at this future time?
c. When the Moon’s orbital period slows to 47 days, tidal braking will cause the Earth’s rotation period to also be 47 days – a condition known as “tidal locking” (1 day = 86400 SI seconds). The current rate of tidal braking of Earth’s rotation is dProt/dt=1.6 milliseconds per century. At this braking rate, how many years will it take for the Earth’s rotation to slow to 47 days?
d. What is the Hill Radius of the Earth in the tidal field of the Sun? Use this equation: Compare rH with the size of the Moon’s orbit in the future when the Earth and Moon are tidally locked that you found in part a. When the Earth and Moon are tidally locked, is the Moon in any danger of wandering away from its orbit around the Earth? Explain your reasoning.
I have already done part a (answer above). I am having particular trouble with part b but would like answers to all parts of the question. You can also check my answer for part a if you wish! Please write legibly and explain your reasoning clearly as you go.



Today, the Moon’s orbit around Earth has a semi-major axis of a=384,400 km and an orbital...
The tidal forces between the Earth and the Moon slowed down the Moon's rotation about its own axis until the rotation period became equal to the Moon's orbital period around the Earth as we observe today. The same effect is also slowing down the Earth's rotation about its own axis and increasing the separation \(D\) between the Moon and the Earth at a rate of \(\Delta D / \Delta t=3.8 \mathrm{~cm}\) per year. In this problem, you can ignore the...
Kepler’s Third Law indicates that the Period (P) of an orbit is related to the semi-major axis (a) of the orbit with: P 2 = ka3 . Kepler noticed that the value of the constant k changes when we observe systems with different central objects. This means that the orbits of all of the planets in the Solar System have the same value for k, but that value is different for the Moon because all of the planets orbit the...
QUESTION 13 A satellite is in Earth orbit with an altitude at perigee of 500 km and an altitude at apogee of 700 km. What is the Eccentricity of the orbit?QUESTION 15 What is the radius of the moon's Sol relative to Earth? Assume: • The mass of the earth is 81.3 times the mass of the moon • The semi-major axis of the moon's orbit about the earth = 3.884 x 105km
6. Given that the distance to the Moon is 384000 km, and taking the Moon’s orbit around Earth to be circular, estimate the speed (in kilometers per second) at which the Moon orbits the Earth. 7. The baseline in Figure 0.19 in the textbook is 100 m and the angle at B is 60 degrees. Using the tangent function, calculate the distance from A to the tree Ch. 1 Discussion Questions 2. The benefit of our current knowledge lets us...
QUESTION 16 The Moon which has mass of about 7.35 1022 kilograms, and it orbits the Earth with an average orbital distance of 384,400 kilometers. Calculate the following for the Moon the magnitude of the average gravitational force exerted by the Earth on the Moon: A. Newtons (use scientific notation and round the coefficient to two decimals) the magnitude of the acceleration due to Earth's gravity at Moon's orbit B. m/s (use scientific notation and round the coefficient to two...
A comet in orbit around the sun has an orbital eccentricity 0.4 and semi-major axis 6 AU. What is the comet's furthest distance from the Sun in AU?
(17%) Problem 5: The Moon orbits around the Earth and also spins on its axis. 33% Part (a) What is the angular momentum of the Moon in its orbit around Earth? 33% Part (b) What is the angular momentum of the Moon in its rotation around its axis? A 33% Part (c) How many times larger is the orbital angular momentum than the rotational angular momentum for the Moon?
Mercury’s orbit has a semi‐major axis of 0.387 AU. a. What is the semi‐major axis of the aberration ellipse for any star from Mercury’s orbit (arcseconds)? [You may use the mass of the Sun as 1.99×1030 kg and assume Mercury is in a circular orbit.] b. Calculate the period (yr) of the aberration orbit?
A satellite in circular orbit around the earth has an orbital speed of 6.2 km/s. What is the period of the orbit? Assume the mass of the Earth is 5.98e24 kg.
The semi-major axis of Callisto's orbit around Jupiter is 0.013 AU. The period of its orbit is 0.046 years. What is Jupiter's mass? A. 0.00029 solar masses B. 0.0010 solar masses C. 0.58 solar masses D. 1.7 solar masses E. 960 solar masses