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1. There are n married couples at a party (so, 2n people). Each person shakes hands with every person other than their spouse

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Answer #1

Each person shakes hands with every person other than their spouse. Thus, each person shakes hands with 2n-2 people. Hence total handshakes are 2n*(2n-2).

But each handshake is counted twice thus the number of handshakes are:

2n*(n-1)

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