Homework Answers
According to law of mass action,
The rate of forward reaction with rate constant k (assume) can be expressed as, rate = k[CH4][H2S]2
The rate of backward reaction with rate constant k' can be expressed as, rate = k'[CS2][H2]4
At equilibrium, the rate of forward reaction is equal to rate of backward reaction. Then,
k[CH4][H2S]2 = k'[CS2][H2]4
k/k' = [CS2][H2]4 / [CH4][H2S]2
This k/k' is called Kc, ie, equilibrium constant of the reaction.
Then Kc = [CS2][H2]4 / [CH4][H2S]2
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