How many moles of NaOH are present in 13.0 mL of 0.180 M NaOH? moles:

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science chemistry

Answer 1

Answer #1

Concentration of NaOH = 0.180 Volume of the solution = 13.0mL X- 1000ml = 0.0130L Number of moles of NaOH = 0.0130L x 0.180 =

Answer 2

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