Question

Question 4 10 pts The force constant of a spring is 500 N/m and its unstretched length is 16 cm. The spring is placed inside a smooth tube that is 16 cm tall (Figure a). A 0.57-kg disk is lowered onto the spring (Figure b). An external force P pushes the disk down further, until the spring is 6.4 cm long (Figure c). The external force is removed, the disk is projected upward and it emerges from the tube (Figured). V 16 cm 6.4 cm (a) (b) (c) (d) In the figure, the compression of the spring in Figure b, in cm, is closest to: 1.1 1.3 1.6 o 1.4 O 1.5

Answer 1

in figure B , the compression is due to the weight

so weight = spring force

mg = kx

0.57*9.8 = 500*x

x = 0.011 m

= 1.1 cm

so the compression in figure b is 1.1 cm