Question

An object is thrown vertically upwards with initial speed 15m/s. After 1s, a second object is thrown up. What is the initial speed that the second object must have to hit the first object at a height of 11m?

Answer 1

12 Nd shab 46 conno =) 42(t-1) = 11+4.9 (t-1)2 96 t = 1.2177 sec. 42 = 11+ 4.9+(1.2177-1) 2 ა — (1.2177-1) ab Now coord 142=51.50 mls 7 of levo 915 t= 1.0434 sec 42 = 14.406010 (0) Loodood Hico 0.9434 = 17.17 m/s. = 142=17-17 mis otriam of From the above solution we can say that there will two speeds of second object of 42 = 51.58 m/s then object het during TO ASES = bx 2520 2 ascent of First af 92 = 17.17 mis then object but during descent of first object