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Previous ProblemProblem List Next Problem 7s +9 s2 +9 (1 point) Find the inverse Laplace transformf(t) = L-1 {F(s)) of the function F(s) = help (formulas) s2 +9 Preview My Answers Submit Answers

Answer 1

F(s) = 7s + 9/s^2 + 9 f(t) = L^-1 {F (s)} = L^-1 {7s + 9/s^2 + 9} = 7 L^-1 {s/s^2 + 9} + 9 L^-1 {1/s^2 + 9} = 7 L^-1 {s/s^2 + 3^2} + 9 L^-1 { 1/s^2 + 3^2} = 7 cos (3t) + 9/3 sin (3t) = 3 sin (3t) + 7 cos (3t) Answer: f(t) = 3 sin (3t) + 7 cos (3t)