Question

I need the following done in C++ formatting and please use while statement instead of for.

Write a program called vectorMismatch.c that that reads 2 vectors of 10 positive integers the prints a count of how many times the 2 vectors have the same value in the same position just as in the previous exercise) and how many times the vectors have the same value but in a different position. Note you have to avoid double-counting -carefully examine the examples below to understand whats wanted Your program must match the examples below perfectly. Your program can assume it is given correct input (20 positive integers). Your program must break down the problem into suitable functions /vectorMismatch Enter vector 1 of 10 positive numbers: 55515 5 255 5 Enter vector 2 of 10 positive numbers: 6661 6 266 6 6 Vectors match in 1 positions. Vectors mismatch in 1 positions.

Answer 1

Please follow the below code and use comments to better understand the code.

SOURCE CODE:

#include <iostream>
#include <vector>
using namespace std;

//Returns the count of matched elements in the two vectors.
int posMatchCount(vector<int> v1,vector<int> v2)
{
int count=0;
int i=0;
while(i<10)
{
if(v1.at(i)==v2.at(i))
count++;
i++;
}
return count;
}

//Returns the count of mis-matched elements in the two vectors.
int MisMatchCount(vector<int> v1,vector<int> v2)
{
int count=0;
int i=0;
while(i<10)
{
int j=0;
while(j<10)
{
//Positions should not be same. so check for i!=j
if(v1.at(i)==v2.at(j) && i!=j)
count++;
j++;
}
i++;
}
return count;
}

//Testing our functions
int main()
{
vector<int> vector1 (10);
cout<<"Enter Vector 1 of 10 positive numbers: ";
// read 10 values into vector 1
for (int i=0; i<10; i++)
cin>>vector1.at(i);

vector<int> vector2 (10);
cout<<"Enter Vector 2 of 10 positive numbers: ";
// read 10 values into vector 2
for (int i=0; i<10; i++)
cin>>vector2.at(i);
  
int count1=posMatchCount(vector1,vector2);
int count2=MisMatchCount(vector1,vector2);
  
//Print the results
cout<<"Vectors match in "<<count1<<" Positions."<<endl;
cout<<"Vectors mismatch in "<<count2<<" Positions."<<endl;
return 0;
}

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SCREENSHOT FOR CODE:

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1 #include <iostream> 2 #include <vector> 3 using namespace std; 4 5 //Returns the count of matched elements in the two vectors 6 int posMatchCount(vectorくint> v1,vectorく1nt>v2) 9 10 int count-0 int i-0; while (i<10) if (v1.at (i)v2.at (i)) 12 13 count++ 15 return count; 18 19 //Returns the count of mis-matched elements in the two vectors 20 int MisMatchCount (vector<int> v1, vector<int> v2) int count-0 int i-0; while(i(10) 25 . 26 27 28 29 30 31 32 int j-e; while (j<10) //Positions should not be same. so check for i!-j if (v1.at(i)v2.at(j) && il-j) count++ 34 36 37 return count; 39 //Testing our functions 40 int main() 41 . 42 43 vectorkint> vector1 (10); cout<<"Enter Vector 1 of 10 positive numbers:" // read 10 values into vector 1 for (int 1-0; 10; i++) 46 cin>>vector1.at(i); 48 vectorKint> vector2 (10) 49 cout<<"Enter Vector 2 of 18 positive numbers:"; 0 read 10 values into vecto 5 for (int i-0; i<10; i++) 52 53 54 int count1-posMatchCount (vector1, vector2); 55 int count2-MisMatchCount (vector1, vector2); 56 57 I/Print the results 58 cout<<"Vectors match in "くくcount!<<" Positions."くくendl; 59 cout<< "Vectors mismatch in "<<count2<<" Positions."<<endl; cin>>vector2.at(i); return Θ

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SAMPLE OUTPUT:

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Result compiled and executed in 36.497 sac(s Enter Vector 1 of 10 positive numbers: 5 5 5 15 5 2 55 5 Enter Vector 2 of 10 positive numbers: 6 6 6 1 6 2 6 6 6 6 Vectors match in 1 Positions Vectors mismatch in 1 Positions Number 2 is Mismatch Result.. compiLed and executed in 31.415 sec Enter Vector 2 of 10 positive numbers: 0 0 Vectors match in Vectors mismatch in 1 Positions 0 0 0 5 4 6 Number 5 is Mismatch 1 Positions

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