Question

A parallel-plate capacitor is formed from two 4.4 cm -diameter electrodes spaced 3.0 mm apart. The electric field strength inside the capacitor is 2.0 ×10^6N/C. What is the charge on the electrodes?

Answer 1

The capacitance of the parallel plate capacitor is, C=64 4.4x102 (8.85x10-alaf4 4x10 )2 (3x10 = 4.4855×10-12 F The charge on the electrode is, Q=C(a) = (4.4855×10-12) (2.0×106)(3x10-3) = 2.69×10-8 C -26.9×10-9 C -26.9 nC