Question

3 Times 10^23 molecules of a monatomic gas undergo the cycle shown below, (the cycle is A rightarrow B rightarrow C rightarrow D rightarrow A) Calculate the work done by (W), heating of (Q), and change in internal energy of (Delta E_int) the gas for each process. Each tick mark represents 1 unit.

Answer 1

no of molecules-3x1023 no of moles (1) for the process A → B work done-P -K) = (8x105) (8-2)-48x10 T,=-= 6023x103° n = 0 5moles 10)(2)_384x10 nR (0.5) (8.3) z B(8x10)(8) 2-MR- (0.5)(8.3) 15.39x10K 5R amount ofheat dQs ·dT=(0.5)|-||15.39 × 10°-3.84×10°-119.83×10°J intemal energy-dU-dQ-dw-119.83x10-48x10-71.83x10 J (2)for the process B-C work donedW-0,since volume is constant 7-1539x10 K3x10) (8) nR 05)83) -5.78x10'k so,dQ-dU-Crd7-(0.5) (578x105-15.39x10s)--59.82/ (3)for the processCD work done-P (,-v) (3x10) (2-8)--18x10J B (3x10)(2 R (05) (83) 144x1 7-578x10Kz(3x10)(2) amount ofheat dQnC,d7-(05) (1.44 x 10%-5.78x105)--45.02x10sJ internal energy-dU=dQ4V-4502x10s +1 8x 10.-27.02x10 (4)for the process D -A work donedW-0,since volume is constant 7-1.44x10°K,7-3.84x10r 3.84×105-1.44×105-14.947