Question

A uniform rod of length L hangs from one end and oscillates with a small amplitude. What is the period of the rods oscillation Recall that the moment of inertia for a rod rotating about one end is -ML 6g 3g 2g 2L 3g
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Answer #1

Option (D) is correct

period of the rods oscillation = 2pi * sqrt(1/mg * L/2) = 2pi * sqrt(mL2/3/mg * L/2) Here, 2pi * sqrt(L/3/g * 1 /2) 2π * sqr

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