Question

20:01 V.VB/s STC Exam-2.pdf Subject: Mechanics of Materials Code: CE 202 Semester 411 QUESTION #2 Beam AE is loaded as shown in the Figure. a) Draw the shear force and the bending moment diagrams for the beam. Clearly mark the numerical values at points A, B, C, D and E. b) What are the maximum bending moment and the maximum shear force? State where they occur 4 kN/m 5kN com Tosmosm/10m Student Name:................... ................... ...... Student ID...... Page 3 of 6

Answer 1

upward force moving from left to right is positive and vice versa.

clockwise moment moving from left to right is positive.
SKN 3 kam & Fyzo RetRC = 6 W o in amg=0 loum Orm Osm loom, -RE+206 + 5*106+3 - ux loux loy=0 and forces Bomdong momen RE= 20 723 KN RB =70877KN Span Colu<2.2m) span (osa, <104) B Untunzo Un=-un at n=0 VA=0 tuman 7087 atn=lou UB=-5.6(KN) -4*14 oun +7087=0 Una 2027 KN atazo UB=2-27 KN a = 008 ve = 2-29 KN Muton3=0 mna -un3 TOP 2 At n=0 mA=0 at na 1.4 MB = -3.92kam. -mn - Urlou (Lou th ) + 788x*=0 mu-4*64 ( 104 th) +708X450 MB=n=0= -3.92 KN mc= –2016 (at left hand side) mc= -2016+3=0.84 kNm (at Just right hand side. span (160<xz<o) SKN ex to 12723 VX-5 +20723=0 un = 2.27 KN mn +5xn--20723(x+1)=0 mne -sut 20723 (nt) anco Mc = 2.723 KNM atn = 0.8 mo= 0.90 UKNm. at n=0 v = 2027 KN aans I Vo= 2.27KN

227 2.2+ ISFD] -5.60 -2022 222 km 07 - 2016 -3-92 manemum Rondong moment = -3.92 KN and manimum shoor Force = -5560kn they occurs because here shear terce Changes sign as we know dm = sheas force dn mis monimum. dm =o dn