def reverseDigits(num): if num<0: return None if num>=0 and num<=9: print(num) return str(num) else: print(num % 10, end="") return str(num%10)+reverseDigits(int(num/10))

def reverseDigits(num):
if num>=0 and num<=9:
print(num)
else:
print(num % 10, end="")
reverseDigits(int(num/10))

Just using print not return Imodify this function to not only return but also keep printing...
Write a python program write a function numDigits(num) which counts the digits in int num. Answer code is given in the Answer tab (and starting code), which converts num to a str, then uses the len() function to count and return the number of digits. Note that this does NOT work correctly for num < 0. (Try it and see.) Fix this in two different ways, by creating new functions numDigits2(num) and numDigits3(num) that each return the correct number of...
Write a method called printReverse() that
takes a string and uses recursion to print the contents of the
string in reverse order. The string itself should
not be reversed; it must be left in its
original form.
The method has the following header:
void printReverse(String s, int i)
where s is a reference to the string, and i is an integer
parameter that you may use as you see fit. You do not need
to code up this method as...
Python: P2 Write a function that reverses a python list using recursion (Chapter 6-3 in our textbook) E.g.: Input: [9, 8, 7, 6, 5, 4, 3, 2, 1, 0] Output: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] Constraints: - List elements are integers - The function should return a reversed array, not print its elements You may use the following code as template: def reverse(my_list, index = None): # your code here
Functions can return a string, not just an int or a float. Write a function called everOrOdd which takes an integer parameter and returns either "Even" or "Odd" based on the value passed. In main, prompt the user for a number, called num, then pass num to evenOrOdd and display the returned value on the screen. Keep doing this until the user enters a zero. Use the following run as an example: Enter a number: 11 Odd Enter a number:...
C++ Functions can return a string, not just an int or a float. Write a function called everOrOdd which takes an integer parameter and returns either "Even" or "Odd" based on the value passed. In main, prompt the user for a number, called num, then pass num to evenOrOdd and display the returned value on the screen. Keep doing this until the user enters a zero. Use the following run as an example: Enter a number: 11 Odd Enter a...
please do in c++Q4. Using recursion only (no loops allowed!), write a C++ function of the form int count7s(int) that when passed a non-negative integer, returns the number of occurrences of the digit 7 in the number. So, for example: count7s(717) → 2 count75(7) →1 count7s(123) → 0 Q5. Write a C++ function of the form string mirrorEnds(string)that when given a string, looks for a mirror image (backwards) string at both the beginning and end of the given string. In other words, zero or...
1. Implement a tostring() member function. This function will return a string representation of the LargeInteger. You should probably used string streams to implement this function. Note that the digits of the large integer are stored in reverse of their display order, e.g. the 1's place (100 ) is in index 0 of digits, the 10's place (101 ) is in index 1, etc. 2. Implement a second constructor for the LargeInteger. This constructor will be used to construct a...
C++
#include <iostream>
using namespace std;
bool checkinventoryid(int id)
{
return id > 0;
}
bool checkinventoryprice(float price)
{
return price > 0;
}
void endProgram()
{
system("pause");
exit(0);
}
void errorID(string str)
{
cout << "Invalid Id!!! " << str
<< " should be greater than 0" << endl;
}
void errorPrice(string str)
{
cout << "Invalid Price!!!" << str
<< " should be greater than 0" << endl;
}
int inputId()
{...
Undecimal to decimal&decimal to undecimal
#Your code here
Thank you!
Binary-to-Decimal In a previous lab, we considered converting a byte string to decimal. What about converting a binary string of arbitrary length to decimal? Given a binary string of an arbitrarily length k, bk-1....bi .box the decimal number can be computed by the formula 20 .bo +21.b, + ... + 2k-1. bx-1- In mathematics, we use the summation notation to write the above formula: k- 2.b; i=0) In a program,...