Question

Chemistry

During the titration experiment, a student used 5 ml of 0.01 M NaOH to neutralize 20ml of vinegar. What is the molarity (M) of the vinegar

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
Chemistry
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • Need help someone please help me like right now.thank you in advance!!!!!! VALUE Volume original vinegar...

    Need help someone please help me like right now.thank you in advance!!!!!! VALUE Volume original vinegar solution Volume diluted vinegar solution Dilution Factor Molarity of NaOH SD 5 ml DZAM TRIAL 1 TRIAL 2 TRIAL 3 HL 10.00mL 0.0 ML SolomL 15. lom 11. 5. 110. 20ml 5.10mL In 10.20m 15. Gou 5.20ml Volume of diluted vinegar sample used in each titration (mL) #2 Initial buret reading (mL) Final buret reading (ml) Volume of NaOH Moles of NaOH Moles of...

  • 4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted...

    4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...

  • I’m so confused on how to do any of this. Name Date General Chemistry I Lab CHE 1211 Data: Concentration of NaOH Trial Titration (to be used as practice) Initial burete eading4.0 ml Final burette...

    I’m so confused on how to do any of this. Name Date General Chemistry I Lab CHE 1211 Data: Concentration of NaOH Trial Titration (to be used as practice) Initial burete eading4.0 ml Final burette reading 20.h m 22.om. Volume of NaOH used Repeat until 2 successful titrations are achieved. Titrations (to be used in calculations) K.Oml 0.bml 35.o mL 22.3 mL 38.5ml ↓ 30.6 mL45.0 mL 49.0 mL 35.5mL50.0 me 22.0mL H. m0 ml 1b.20 m 4.5ml Initial burette...

  • Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1....

    Questions (Pay attention to units and significant figures for the calculations sted molarity of NaOH 1. For each of the following circumstances indicate whether the calculated molarity of would be lower, higher or unaffected. Explain your answer in each case a. The inside of the pipet used to transfer the standard HCl solution was wet with water. b. You added 40 mL of water to the titration flask rather than 25 mL. c. The buret, wet with water, was not...

  • A solution of 0.270 M NaOH is used to neutralize 35.0 ml of acetic acid in...

    A solution of 0.270 M NaOH is used to neutralize 35.0 ml of acetic acid in vinegar. If 28.0 ml NaOH is used to reach the end point. What is the molarity of vinegar used?

  • Acid-Base Titration PRE-LABORATORY ASSIGNMENT This assignment must be completed in your notebook prior to attending pre-lab...

    Acid-Base Titration PRE-LABORATORY ASSIGNMENT This assignment must be completed in your notebook prior to attending pre-lab lecture. 1. Sketch a picture of a 50 mL buret. Clearly label the location on the 0.00 mL line and the 50.00 mL line on the buret. Refer to appendix 5E for information about a buret. 2. Write the balanced chemical equation that will be used during this titration experiment. 3. Assume a student performed the acid-base titration experiment that you will be doing...

  • 1. In the second step she prepared the vinegar solution for the titration in the following...

    1. In the second step she prepared the vinegar solution for the titration in the following manner 25.0 mL of vinegar were diluted to 250.0 mL in a volumetric flask, and 25.0 mL of this diluted solu- tion required 8.27 mL of the above standardized NaOH (gquestion 5a) to reach the phenolphthalein endpoint. What is the molarity of the acid as it was titrated (diluted vinegar)? a. Use the dilution equation to determine the molarity of the acid prior to...

  • I construct a 2 part experiment for titration. I use 5 ml of vinegar and Tirate...

    I construct a 2 part experiment for titration. I use 5 ml of vinegar and Tirate na 20ml of Im of Naot. I reach a pH of 12.3 at the end point of the titration In the second part of the experiment I use 15mL of vinegar (acetic acid in the beaker and end up only using 17ml of Im of Naoh. what is the molanty of vinegara

  • Trial one Trial two Trial three Volume of oxalic acid (mL) 10.1 mL 10.2 mL 10.1...

    Trial one Trial two Trial three Volume of oxalic acid (mL) 10.1 mL 10.2 mL 10.1 mL Moles of oxalic acid (moles) 0.0026 0.0026 0.0026 Initial volume of NaOH (mL) 18.7 mL 26.5 mL 34.6 mL Final volume of NaOH (mL) 26.5 mL 34.6 mL 42.6 mL Delivered volume of NaOH (moles) 7.8 mL 8.1 mL 8 mL Moles of NaOH (moles) 0.0052 0.0052 0.0052 Molarity of NaOH (M) 0.6667 0.6420 0.65 Average Molarity NaOH (M) 0.65 Concentration oxalic acid...

  • Section Acid-Base Titration Team LAB 10 Results A. Concentration of Acetic Acid in Vinegar 1. Brand:...

    Section Acid-Base Titration Team LAB 10 Results A. Concentration of Acetic Acid in Vinegar 1. Brand: Great Value Volume: 5.0mL. (% on label) 5% 2. Molarity (M) of NaOHO.099M Trial 3 Trial 1 Trial 2 1.4 mL 0.7 mL 1.2 ml 3. Initial NaOH level in buret 41.5mL 41.3 mL 41.5ml 4. Final NaOH level in buret 5. Volume (ml) of NaOH used 6. Average volume (ml) 7. Average volume in liters (L) 8. Moles of NaOH used in titration...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT