Question

80 grams of oxygen and 40 grams hydrogen gas occupy separate, equal sections of 200 liter tank. The divide is removed and the gases are allowed to mix and react with each other. The temperature is kept constant at 110 °C, throughout the process. a) find the pressure of each gas in the separate containers. b) find the pressure after the reaction ends.

Answer 1

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Initially PV = nRT pa nRT ; To 11oC = 2131110 3831 V= 200 - 200 X Jo Jun - = 0.2 m3 Container I- mi so = 10/4 = 2.5 m3 . P = - 3198x104 Pas 2.5x8314x383 02 Containe 2 M23 40 = 20 P22 208 8:3/4 X333 - 0.2 DSS18X10% pa After mining v=2v = 280 2 = 0.4ms 7. 383k. n = nitn2 = 2072.5 - 22'5 pa mrt - 225X8314 X 383 0.4. > 1.79 x105 Pa