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Keep getting this wrong. I got .82

In the figure, a ball of mass M and radius R rolls
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Answer #1

Here by energy conservation,

0.5 MV^2 + 0.5IW^2 = Mgh

0.5MV^2 +0.5* BMR^2*V^2/R^2=Mgh

0.5 MV^2 + 0.5BMV^2 = Mgh

(1+B) MV^2 /r=2Mgh/r

(1+B)( 2.25 Mg -Mg)= 2Mg*(0.445/0.489)

1+B = 2×(0.445/0.489)/1.25

B = 2×(0.445/0.489)/1.25 - 1

B = 0.456 Answer

  

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