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In an experiment designed to measure the magnitude of a uniform magnetic field, electrons were accelerated from rest through a potential difference of 350V and then enter a magnetic field that is perpendicular to the velocity vector of the electrons. The electron travel along a curved path because of magnetic force exerted on them, and the radius of the path is measured to be 7.5 cm.
-> potential difference,
V = 350 V
-> radius of path, r = 7.5 cm = 0.075 m
-> electron mass. m = 9.11*10-11 kg
-> charge of electron, q = -1.6*10-19 C
To find the magnitude of the magnetic field, we use the conservation of energy,
initial energy = final energy
(K + U)i = (K+U)f
(K + U)i - (K+U)f = 0
(Ki - Kf) + (Ui-Uf) = 0
(1/2*m*Vi2) -(1/2*m*Vf2) + (q*
V
) = 0
(1/2*m*Vi2) -0 + (q*
V
) = 0
0.5 * 9.11 *10-11 * Vi2+ (-1.6*10-19 )*350 = 0
=> Vi = 1.11*107 m/s
-> magnetic field, B = (m*Vi) / (q*r)
=> B = (9.11*10-11 * 1.11*107) / (1.6*10-19 * 0.075)
=> B = 8.4 * 10-4 T
-> The angular speed of the electron


-> If there is sudden voltage surge causing the acceleration voltage to increase to 500v, will result in a speed increase of the electron which leads to the increase of the radius of the path taken by the electron. Hence, as both v and r increases, the angular speed which is (v/r) will neutralise and no change occurs to the angular speed.
-> If the experiment is conducted in a non uniform magnetic field, the motion of the electrons will be complex. the path taken by the electron can be a spiral and completely depends on the shape of the magnetic field.
I will really appreciate if someone would help me out with this problem. Thank you. P.S....
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