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(1 point) Evaluate the surface integral || (3x yi – 3yzj + zxk) · dS. JJ s . Where S is the part of the paraboloid z = 9 – x2

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Solution : Surface Integral [[(3097 – 3yaj +zxk). As Sis the part of the paraboloidz=9-x - 72 that lies above the square 0<x<

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